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7x^2-12=-17x
We move all terms to the left:
7x^2-12-(-17x)=0
We get rid of parentheses
7x^2+17x-12=0
a = 7; b = 17; c = -12;
Δ = b2-4ac
Δ = 172-4·7·(-12)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-25}{2*7}=\frac{-42}{14} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+25}{2*7}=\frac{8}{14} =4/7 $
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